Asked by Christian
what is the ph solution obtained by mixing 25.00 ml of 0.250 ml HCl and 25.00ml of 0.125M NaOH
Answers
Answered by
Liz
0.025L x 0.25 mol HCl/1L = mol HCl
0.025L x 0.125 mol NaOH/1L = mol NaOH
HCl + NaOH --> H2O + NaCl
You have twice as many moles of HCl as NaOH, so there will be left over HCl.
Find the moles of HCl left over and divide by the combined volumes to get its molarity. That will be the molarity of H+. Take the negative log.
0.025L x 0.125 mol NaOH/1L = mol NaOH
HCl + NaOH --> H2O + NaCl
You have twice as many moles of HCl as NaOH, so there will be left over HCl.
Find the moles of HCl left over and divide by the combined volumes to get its molarity. That will be the molarity of H+. Take the negative log.
Answered by
Christian
Thank you very much! This was very helpful:)
Answered by
Richard
so whats the answer,
Answered by
Anonymous
1.2