Asked by Joel
The amount of fill(weight of contents)put into a glass jar of spaghetti sauce is normally distributed with mean=850g and standard deviation=8g.the probability that a random sample of 24 jars has a mean weight greater than 848g is?need help
Answers
Answered by
PsyDAG
Z = (sample mean-mean)/SEm (Standard Error of the mean)
SEm = SD/√(n-1)
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to that Z score.
SEm = SD/√(n-1)
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to that Z score.
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