Asked by John

In 2010 a city raised $5,999,400 in tax revenue by charging each taxpayer the same amount. For 2011 there has been a net loss of 12 taxpayers, necessitating an increase fo $200 per taxpayer in order to maintain the tax revenue of $5,999,400. How many taxpayers were there in 2010?
Answered by Henry
X-Taxpayers in 2010.

(X - 12)Taxpayers in 2011.

$200(X - 12) = $5,999,400.
X - 12 = 29997 Taxpayers in 2011.


Answered by Henry
X - 12 = 29997,
X = 30009 Taxpayers in 2010.
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