What is the height of a triangle whose base is 9.4 centimeters and whose area is 132.54 square centimeters?

Answer 1

Area=(1/2)*base*hight

A=(b*h)/2

A=Area=132.54cm^2

b=base=9.4cm

h=hight

A=(b*h)/2

132.54=(9.4*h)/2 Multiply with 2

265.08=9.4*h Divide with 9.4

h=265.08/9.4

h=28.2 cm