Asked by mlb
The length of a rectangle is 3 in. more than twice its width. If the perimeter of the rectangle is 18 in., find the width of the rectangle.
Answers
Answered by
bobpursley
2w=l-3
2w + 2l=18
solve.
2w + 2l=18
solve.
Answered by
mlb
Thank you.
Can you help me with this one:
Stan invested $13,000, part at 17% and part at 2%. If the total interest at the end of the year is $1,910, how much did he invest at 17%?
Can you help me with this one:
Stan invested $13,000, part at 17% and part at 2%. If the total interest at the end of the year is $1,910, how much did he invest at 17%?
Answered by
DrBob222
Let Y = amount invested at 17%.
Then 13,000 - Y = amount invested at 2%.
Y + (13,000 - Y)*0.02 = 1910.
Solve for Y.
Your questions are likely to be ignored if you post follow questions to an earlier one. It is better to post a different question under Post a New Question rathan than to piggy back on one to which a response has been given.
Then 13,000 - Y = amount invested at 2%.
Y + (13,000 - Y)*0.02 = 1910.
Solve for Y.
Your questions are likely to be ignored if you post follow questions to an earlier one. It is better to post a different question under Post a New Question rathan than to piggy back on one to which a response has been given.
Answered by
mlb
Ok thank you
Now I am completely lost
Now I am completely lost
Answered by
DrBob222
You don't understand something about the answer? What? Please be specific.
Answered by
mlb
Correct, I do not understand how to solve for Y
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