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At the top of a pole vault, an athlete actually can do work pushing on the pole before releasing it. Suppose the pushing force...Asked by blah
At the top of a pole vault, an athlete actually can do work pushing on the pole before releasing it. Suppose the pushing force that the pole exerts back on the athlete is given by F(x)= (150 N/m)x - (180N/m^2)x^2 acting over a distance of 0.20 .
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Answered by
Damon
integrate F dx
work from x = 0 to x = X is
W = (150/2)X^2 + (180/3)X^3
so put in 0.2 for X
work from x = 0 to x = X is
W = (150/2)X^2 + (180/3)X^3
so put in 0.2 for X
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