Asked by leon
sum (n*2^n)/(2^n +3^n) [n to infinity]
conv or div ? and how to get that?
thank you!
conv or div ? and how to get that?
thank you!
Answers
Answered by
Reiny
using an intuitive approach ....
the sum = 1(2)/(2+3) + 2(4)/(4+9) + 3(8)/(8+27) + 4(16)/(16+81) + 5(32)/(32+243) + ..
= .4 + .6153 + .6857 + .65979 + .5818 + ...
after the 3rd term each successive term appears to get smaller
e.g. term(10) = 10(1024)/(1024 + 59049) = .17045
term(100) = 2.46x10^-16
can you do anything with that?
the sum = 1(2)/(2+3) + 2(4)/(4+9) + 3(8)/(8+27) + 4(16)/(16+81) + 5(32)/(32+243) + ..
= .4 + .6153 + .6857 + .65979 + .5818 + ...
after the 3rd term each successive term appears to get smaller
e.g. term(10) = 10(1024)/(1024 + 59049) = .17045
term(100) = 2.46x10^-16
can you do anything with that?
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