how much heat is required to completely vapporize 2.3 grams of ice starting at -50 degrees Celsius? (the specific heat of ice is 2.0 J/g.C; the specific heat of water is 4.184 J/g.C; the heat of fusion is 333 J/g; and the heat of vaporization is 22601 J/g)

Answer 1

q1 = heat to move solid ice from -50 C to zero C.
q1 = mass ice x specific heat ice x (Tfinal-Tinitial).

q2 = heat to melt ice at zero C to liquid water at zero C.
q2 = mass ice x heat fusion.

q3 = heat to move liquid water from zero C to 100 C
q3 = mass water x specific heat water x (Tfinal-Tinitial)

q4 = heat to convert liquid water at 100 C to vapor at 100 C.
q4 = mass water x heat vap.

qTotal = q1 + q2 + q3 + q4