Asked by roshan

calculate the molar solubility of barium fluoride in water at 25 degrees C. The solubility product constant for BaF2 at this temperature is 1.0x10^-6

14 years ago

Answered by DrBob222

See the post above.

14 years ago

Answered by Garry P.

6.3x10^-3

7 years ago

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