Question

A harmonic wave is traveling along a rope.
The oscillator that generates the wave com-
pletes 44.0 vibrations in 26.9 s. A given crest
of the wave travels 359 cm along the rope in a
time period of 11.6 s.
What is the wavelength?
Answer in units of m.
bobpursley
freq=44.26.9

v= 3.59m/11.6s

lambda= v/f
bobpursley
f=44/26.9

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