Asked by mo

lim (4sin2x - 3x cos5x)/(3x/2 +(x^2)cscx )
x->0
Answered by bobpursley
L'Hoptial's rule applies to this.


I get for the numerator..

8cos2x - 3cos5x - 15x sin5x

and the denominator...
3/2 + 2x csc x + x^2 d cscx/dx

so the limit looks to be
5/ (3/2) = 10/3

check me.
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