Asked by Esther
Hooker's law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is 39cm when the weight is 3kg, what is the distance when the weight is 9kg?
Thank you, before hand.
Thank you, before hand.
Answers
Answered by
tchrwill
39/3 = 13 cm/kg, the spring "rate" of the spring.
Therefore, the d for 9kg is
d = 13cm/kg x 9kg = 117cm.
Therefore, the d for 9kg is
d = 13cm/kg x 9kg = 117cm.
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