The 10 km/h velocity change is 2.78 m/s
The time required to accomplish that velocity change is (deltaV)/a
= (2.78 m/s)/0.82 m/s^2 = 3.39 s
The displacement will be the average velocity multiplied by that time.
X = (90 km/h)*3.39 s* 1h/3600 s
= ___ meters
A certain car is capable of accelerating at a
uniform rate of 0.82 m/s2.
What is the magnitude of the car’s displace-
ment as it accelerates uniformly from a speed
of 85 km/h to one of 95 km/h?
Answer in units of m.
1 answer
1 answer