Asked by Sam
In 2002 John Daly led the PGA tour in driving distance with an average drive of 305.5 yards and a standard deviation of 17.2 yards. Assuming that these distances are normally distributed, 80% of John Daly's drives are longer than what distance?
Answers
Answered by
PsyDAG
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the Z score related to that proportion. Insert values in the equation above and solve for the score.
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the Z score related to that proportion. Insert values in the equation above and solve for the score.
Answered by
Anonymous
The breaking strength (in pounds) of a certain new synthetic is normally distributed, with a mean of 170 and a variance of 4. The material is considered defective if the breaking strength is less than 166 pounds. What is the probability that a single, randomly selected piece of material will be defective?
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