Asked by Kiksy
Hello,
I am learning about Taylor series in school, but they are quite confusing..
Can you please explain how I should do this problem? Thank you very much!
What is the Taylor polynomial of order 5 approximation to sin(1.5) ?
I know the series of sinx = x - ((x^3)/(3!)) + ((x^5)/(5!))-...+...
but where do i go from here?
THANK YOU~
I am learning about Taylor series in school, but they are quite confusing..
Can you please explain how I should do this problem? Thank you very much!
What is the Taylor polynomial of order 5 approximation to sin(1.5) ?
I know the series of sinx = x - ((x^3)/(3!)) + ((x^5)/(5!))-...+...
but where do i go from here?
THANK YOU~
Answers
Answered by
MathMate
If
"I know the series of sinx = x - ((x^3)/(3!)) + ((x^5)/(5!))-...+..."
this is given, you only have to substitute 1.5(in radians) as x into the above series up to x^5 as requested.
For example:
sin(1.5)=1.5-1.5^3/3!+...
However, in practice, I would not stop at order 5 because the error is excessive for this value of x.
"I know the series of sinx = x - ((x^3)/(3!)) + ((x^5)/(5!))-...+..."
this is given, you only have to substitute 1.5(in radians) as x into the above series up to x^5 as requested.
For example:
sin(1.5)=1.5-1.5^3/3!+...
However, in practice, I would not stop at order 5 because the error is excessive for this value of x.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.