Question
Emily’s dad pays her for picking strawberries. Each hour she works he increases her pay. The first hour she earns two cents, the second hour she earns four cents, the third hour eight cents, and so on, doubling the amount each hour. How much money will she earn if she works six hours? How much money will she earn after ten hours? How many hours will she need to work to earn at least $5.00?
Answers
Ms. Sue
Hour 1: 0.02
Hour 2: 0.04
Hour 3: 0.08
Hour 4: 0.16
Hour 5: 0.32
Hour 6: 0.64
Add these 6 numbers together to find your first hour.
Keep doubling the preceding number to find the other two answers.
Hour 2: 0.04
Hour 3: 0.08
Hour 4: 0.16
Hour 5: 0.32
Hour 6: 0.64
Add these 6 numbers together to find your first hour.
Keep doubling the preceding number to find the other two answers.
what do u mean by add your six numbers to get your first hour.
Ms. Sue
Sorry -- it should add those numbers to find your first ANSWER.
thanks i figured it out
your numbers form a geometric sequence where
a = .02
r = 2
Term(6) = ar^5 = .02(2^5) = .02(32) = .64
term(10) = ar^9 = .02(2^9) = .02(512) = 10.24
ar^(n-1) > 5.00
.02(2)^(n-1) > 5
2^(n-1) > 250
I know 2^7 = 128 and 2^8 = 256
so what do you think?
a = .02
r = 2
Term(6) = ar^5 = .02(2^5) = .02(32) = .64
term(10) = ar^9 = .02(2^9) = .02(512) = 10.24
ar^(n-1) > 5.00
.02(2)^(n-1) > 5
2^(n-1) > 250
I know 2^7 = 128 and 2^8 = 256
so what do you think?
$5.10, calculated as follows:
$.02 + $.04 = $.06 + $.08 = $.14 +$.16 = $.30 + $.32 = $.62 + %,64 = $1.26 + $1.28 = $2.54 + $.56 = $.10
$.02 + $.04 = $.06 + $.08 = $.14 +$.16 = $.30 + $.32 = $.62 + %,64 = $1.26 + $1.28 = $2.54 + $.56 = $.10
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