Asked by chalulu

IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. Find the x- score that corresponds to a z-score of 2.33.
Answered by PsyDAG
Z = (score-mean)/SD

2.33 = (x-100)/15

Solve for x.
Answered by Dane
143.2
Answered by Hellazo
134.95
Answered by Momen zidan
x=mean+score * SD
x=100+2.33*15=134.95
so x=134.95
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