A person who is 6 feet tall walks away from a 50-foot silo toward the tip of the silo's shadow. At a distance of 32 feet from the silo, the person's shadow begins to emerge beyond the silo's shadow.How much farther must the person walk to be completely out of the silo's shadow?
2 answers
You need to set up the situation with a diagram using similar triangles. Then, use the Pythagorean Theorem.
Let x be the additional distance to the end of the shadow. Using the similar triangles method suggested by Michael, the ratios of the two per[pendicular sides are:
50/(32+x)= 6/x
Solve for x.
50 x = 192 + 6x
44 x = 192
x = ?
50/(32+x)= 6/x
Solve for x.
50 x = 192 + 6x
44 x = 192
x = ?
1 answer