Asked by arty
                what are the steps to solve for x
2x^2-1/x^2=0
            
            
        2x^2-1/x^2=0
Answers
                    Answered by
            Damon
            
    2 x^2 - 1/x^2 = 0 ???
2 x^4 = 1
x^4 = 1/2
x^2 = (1/2)^.5 or -(1/2)^.5
x = (1/2)^.25 or -(1/2)^.25 or i(1/2)^.25 or -i(1/2)^.25
    
2 x^4 = 1
x^4 = 1/2
x^2 = (1/2)^.5 or -(1/2)^.5
x = (1/2)^.25 or -(1/2)^.25 or i(1/2)^.25 or -i(1/2)^.25
                    Answered by
            arty
            
    thank you.i am trying to sove for critical numbers. the book is giving me an answer of
x=+square root 2/2
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x=+square root 2/2
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                    Answered by
            bobpursley
            
    I am wondering if the problem then is this:
(2x^2-1)/x^2=0
2x^2=1
x= +- sqrt (1/2)
but of course, multiplying that by sqrt(2/2) one gets
x= +- sqrt (2/4)= +- .5 sqrt 2
    
(2x^2-1)/x^2=0
2x^2=1
x= +- sqrt (1/2)
but of course, multiplying that by sqrt(2/2) one gets
x= +- sqrt (2/4)= +- .5 sqrt 2
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