Question
A system consists of three particles, each of mass 2.10 g, located at the corners of an equilateral triangle with sides of 22.0 cm.
Calculate the potential energy of the system.
Please help me what formula to use please
Calculate the potential energy of the system.
Please help me what formula to use please
Answers
Relative to a situation where the masses are widely separated, the potential energy of the equilateral configuration will be negative. That is because it will require work to separate them.
A single mass m has no potential associated with it.
When you add a second mass m at distance a, there will potential anergy equal to
-G m^2/a
When you bring in a third mass m at distance a from both, you add potential energy equal to -2G m^2/a
The total potential energy is therefore
-3G m^2/a
G is the universal constant of gravity, m = 0.0021 kg and a = 0.22 m
Expect a very small number.
A single mass m has no potential associated with it.
When you add a second mass m at distance a, there will potential anergy equal to
-G m^2/a
When you bring in a third mass m at distance a from both, you add potential energy equal to -2G m^2/a
The total potential energy is therefore
-3G m^2/a
G is the universal constant of gravity, m = 0.0021 kg and a = 0.22 m
Expect a very small number.
The constant G can be found at
http://en.wikipedia.org/wiki/Gravitational_constant
http://en.wikipedia.org/wiki/Gravitational_constant
Thank you very much sir!
Related Questions
Four particles, one at each of the four corners of a square with 2.5-m-long edges, are connected by...
A system consists of two particles. Particle 1 with mass 2.0 kg is located at (2.0 m, 6.0 m) and has...
a system consists of particles of masses 5, 2 and 3g located at (1, 0, -1), (1, 2, 1) and (1, -1, -3...