Asked by susan marshall

6{[3(x 4)+16]-[3(4x-3)+4]}
how do I solve this expression I cant figure this out
Answered by Anonymous
What is: 3(x 4)?

3(x+4) OR 3(x-4)

If 3(x 4)=3(x+4) then:

3(x+4)=3*x+3*4=3x+12

3(x+4)+16=3x+12+16=3x+28

3(4x-3)=3*4x-3*3=12x-9

3(4x-3)+4=12x-9+4=12x-5

3(x+4)+16-3(4x-3)+4=(3x+28)-(12x-5)=
3x+28-12x-(-5)=3x+28-12x+5= -9x+33

6{[3(x 4)+16]-[3(4x-3)+4]}=6*(-9x+33)=
-6*9x+6*33= -54x+198



If 3(x 4)=3(x-4) then:

3(x-4)=3*x-3*4=3x-12

3(x-4)+16=3x-12+16=3x+4

3(4x-3)=3*4x-3*3=12x-9

3(4x-3)+4=12x-9+4=12x-5

3(x-4)+16-3(4x-3)+4=(3x+4)-(12x-5)=
3x+4-12x-(-5)=3x+4-12x+5= -9x+9

6{[3(x 4)+16]-[3(4x-3)+4]}=6*(-9x+9)=
-6*9x+6*9= -54x+54




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