Did you mean
(v-7)/v - (2v-9)/v ??
confirm please by using brackets.
Subtract. Simplify if possible.
v-7/v-2v-9/5v. Thank you for your help.
3 answers
I'm sorry, I forgot the 5, it was 5v.
It didn't have brackets, that's why I didn't put any, but it goes like this:
Subtract. Simplify if possible.
v-7/v -2v-9/5v.
Note: the slashes mean fraction form, in other words, it's v-7 on the top and v, alone in the bottom. The same goes for 2v-9, this goes on top and 5v in the bottom, fraction form. Thank you, before hand.
It didn't have brackets, that's why I didn't put any, but it goes like this:
Subtract. Simplify if possible.
v-7/v -2v-9/5v.
Note: the slashes mean fraction form, in other words, it's v-7 on the top and v, alone in the bottom. The same goes for 2v-9, this goes on top and 5v in the bottom, fraction form. Thank you, before hand.
You are missing my point, I know the / is division
The way you typed it, it means:
v -(7/v) - 2v - (9/5)(v)
I have a feeling you meant:
(v-7)/v - (2v-9)/(5v)
so the common denominator is 5v
then
5(v-7)/(5v) - (2v-9)/(5v)
= (5(v-7) - (2v-9))/(5v)
= (5v - 35 - 2v + 9)/(5v)
= (3v - 26)/(5v)
The way you typed it, it means:
v -(7/v) - 2v - (9/5)(v)
I have a feeling you meant:
(v-7)/v - (2v-9)/(5v)
so the common denominator is 5v
then
5(v-7)/(5v) - (2v-9)/(5v)
= (5(v-7) - (2v-9))/(5v)
= (5v - 35 - 2v + 9)/(5v)
= (3v - 26)/(5v)