Asked by Carmen
The base length of the triangle with vertices A(1,1, B(9,1), C(5,5)is multipliend by 2.Describe the effect of the change on the area.
can someone help me on this one.. am stuck
can someone help me on this one.. am stuck
Answers
Answered by
Henry
A = (b/2) *h,
Multiply the base by 2 and get:
A = b*h,
So the area is doubled.
Let's calculate the area of the given
triangle.
A(1,1), B(9,1), C(5,5).
AB = 9 - 1 = 8 = base.
(AC)^2 = (5-1)^2 + (5-1)^2,
(AC)^2 = 16 + 16 = 32,
AC = sqrt32 = 5.66.
(b/2)^2 + h^2 = (AC)^2,
4^2 + h^2 = 32,
h^2 = 32 - 16 = 16,
h = 4.
A = (b/2) * h,
A = (8/2) * 4 = 16.
Double the base:
A = (16/2) * 4 = 32.
Multiply the base by 2 and get:
A = b*h,
So the area is doubled.
Let's calculate the area of the given
triangle.
A(1,1), B(9,1), C(5,5).
AB = 9 - 1 = 8 = base.
(AC)^2 = (5-1)^2 + (5-1)^2,
(AC)^2 = 16 + 16 = 32,
AC = sqrt32 = 5.66.
(b/2)^2 + h^2 = (AC)^2,
4^2 + h^2 = 32,
h^2 = 32 - 16 = 16,
h = 4.
A = (b/2) * h,
A = (8/2) * 4 = 16.
Double the base:
A = (16/2) * 4 = 32.
Answered by
Anonymous
The area is multiplied by 4
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