given:

f(x)=x^2
g(x)=2^x
find:
g^-1(f(3))to the nearest tenth

can any one please explain to me how to find the inverse of g of f of 3????

2 answers

g(x) = 2^x
let y = 2^x
then the inverse function is
x = 2^y
or
y = ln x/ln 2

so g-1(x) = ln x/ ln 2

but f(3) = 3^2 = 9
so g-1(f(3) = ln 9/ln 2 = 3.2
what is "ln x/ln 2"???????