Asked by Rebekah
...A dioxin-contaminated water source contains 0.044% dioxin by mass. How much dioxin is present in 6.5 L of this water? (Assume that the density of the solution is 1.00 g/mL.)
thanks
thanks
Answers
Answered by
bobpursley
6500grms*.00044= XXXX grams
Hint it is between 1 and 6 grams
Hint it is between 1 and 6 grams
Answered by
DrBob222
0.044% means 0.044 g/100 g soln or
0.044 g/100 mL (Technically this is 0.044 g/(100-0.044) but for very dilute solutions we usually ignore that small difference.
0.044 g/100 is how many g in 6.5L? That is
0.044 g x 6,500 mL/100 mL = ??
0.044 g/100 mL (Technically this is 0.044 g/(100-0.044) but for very dilute solutions we usually ignore that small difference.
0.044 g/100 is how many g in 6.5L? That is
0.044 g x 6,500 mL/100 mL = ??
Answered by
Rebekah
so would it be 2.86?
Answered by
bobpursley
yes, right.
Answered by
Rebekah
thanks:)
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