Asked by candy
0.3g of clotrimazole (C22H17ClN2) was dissolved in 80ml of anhydrous acetic acid. This was titrated with 0.1M perchloric acid using 0.3ml of naphtholbenzein as indicator until the colour changes from brownish-yellow to green.
1ml of 0.1M perchloric acid is equivalent to 34.48mg of clotrimazole (C22H17ClN2).
1st titration= A ml of 0.1M perchloric acid was used.
2nd titration= B ml of 0.1M perchloric acid was used.
How do I calculate the % of clotrimazole?
1ml of 0.1M perchloric acid is equivalent to 34.48mg of clotrimazole (C22H17ClN2).
1st titration= A ml of 0.1M perchloric acid was used.
2nd titration= B ml of 0.1M perchloric acid was used.
How do I calculate the % of clotrimazole?
Answers
Answered by
DrBob222
A mL x (34.48 mg cmpd/1mL) = ??mg cmpd. Convert to grams, then
(grams/0.3)*100 = %
B mL is done the same way.
(grams/0.3)*100 = %
B mL is done the same way.
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