Asked by Tayler
What is the pH of a solution made by dissolving the 37 g of KOH in 500 mL of water, with no buffer in it?
Answers
Answered by
DrBob222
moles KOH = 37g/molar mass KOH.
moles OH- = moles KOH and M KOH = moles/L soln; therefore,
pOH = -log(OH^-) and convert to pH.
moles OH- = moles KOH and M KOH = moles/L soln; therefore,
pOH = -log(OH^-) and convert to pH.
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