Asked by DMITRIC

A box is lifted with a pry bar, by slipping the bar under the box and lifting up on the bar. If the pry bar is 2m in length and it is grasped at the end, and the box is located at the opposite end, the fulcrum, with its center of gravity at a distance of 0.5 m from the fulcrum.

what is the size of the force required to lift the box if the box has a weight of 100N?

CAN SOMEONE TELL ME IF I AM CORRECT?
.5 X 100 = 50Nm / 2m = 25N
Answered by drwls
0.5m * 100N = F * 2m
Solve for unknown F
F = 25 N

Right answer; bad notation.
Answered by DMITRIC
Thanks Mr. drwls for your input, but I do not follow the above notation. is * multiplication? forgive my ignorance...:(
Answered by Damon
Yes * means multiply
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