Asked by jerome
How many moles of ammonia gas can be produced from the reaction of 3.0L of N2 and 3.0L of H2 according to the following equation:
N2(g) + 3H2(g)---> 2NH3(g)?
N2(g) + 3H2(g)---> 2NH3(g)?
Answers
Answered by
DrBob222
You have a limiting reagent problem. In gaseous reactions you may use L as if they were moles.
Using the coefficients in the balanced equation, convert L N2 to L NH3. Do the same for L H2 to L NH3. The two answers won't be the same; the correct value in limiting reagent problems is ALWAYS the smaller one and the reagent producing that value is the limiting reagent. Take the smaller value (in L) and convert to moles remembers that 1 mole of a gas occupies 22.4 L at STP.
Using the coefficients in the balanced equation, convert L N2 to L NH3. Do the same for L H2 to L NH3. The two answers won't be the same; the correct value in limiting reagent problems is ALWAYS the smaller one and the reagent producing that value is the limiting reagent. Take the smaller value (in L) and convert to moles remembers that 1 mole of a gas occupies 22.4 L at STP.
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