Asked by Zukii
Differentiate the following ( do not simplify)
a) ln(√sinx)
a) ln(√sinx)
Answers
Answered by
MathMate
Use the chain rule:
d(ln(√sin(x)))/dx
=[1/(√sin(x))]*d√(sin(x))/dx
=[1/(√sin(x))]*[1/(2√(sin(x)))]*d(sin(x))/dx
=[1/(√sin(x))]*[1/(2√(sin(x)))]*cos(x)
d(ln(√sin(x)))/dx
=[1/(√sin(x))]*d√(sin(x))/dx
=[1/(√sin(x))]*[1/(2√(sin(x)))]*d(sin(x))/dx
=[1/(√sin(x))]*[1/(2√(sin(x)))]*cos(x)
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