Question

A ball moving with a speed of 26 m/s strikes an identical ball that is initially at rest. After the collision, the incoming ball has been deviated by angle 1 = 50° from its original direction, and the struck ball moves off at angle 2 = 29° from the original direction (Fig. 9-37). What are the speeds of the two balls after the collision

i cant get it started

i know its momentum, and we need vectors but i cant budge it... please help

Answer 1

initial x momentum = 26 m


final x momentum = V1 m cos 50 + V2 m cos 29

initial y momentum = 0

final y momentum = V1 m sin 50 - V2 m sin 29

final x momentum = initial x momentum
final y momentum = initial y momentum
m cancels everywhere
2 linear equations, 2 unknowns V1 and V2

Answer 2

well, the answer is simple. it is one.