Asked by Plzz helpp

The weights of adult males are normally distributed with a mean of 172 lb and a standard deviation of 29 lb.
1.Find the weight that divides the upper 2% of weights from the lower 98%.


Can anyone please explain how to do this,I have no idea from where to begin.

Thanks.

Answers

Answered by PsyDAG
Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the Z score that fits that proportion.

Insert values in above equation to find weight score.
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