Asked by Jeromino
The maximum, range of a projectile is directly proportional to the square of its velocity. A baseball pitcher throws a ball at 60 mph, with a maximum range of 242 ft. What is his maximum range if he throws the ball at 70 mph?
Answers
Answered by
Reiny
"The maximum, range of a projectile is directly proportional to the square of its velocity"
-----> range = k(velocity)^2 , where k is a constant
when vel=60, range = 242
242 = k(3600)
k = 242/3600 = 121/1800
r = (121/1800)v^2
when v=70
r = (121/1800)(4900) = 5929/18 = appr. 329 ft
-----> range = k(velocity)^2 , where k is a constant
when vel=60, range = 242
242 = k(3600)
k = 242/3600 = 121/1800
r = (121/1800)v^2
when v=70
r = (121/1800)(4900) = 5929/18 = appr. 329 ft
Answered by
Jeromino
Thanks a bunch
Answered by
Varun
The range of projectile is directly proportional to
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