Asked by curtisgurl
I need help with: solving and check for extraneous solutions.
sqrt y+9=1
sqrt y+9=1
Answers
Answered by
Michael
Is your equation √(y+9) = 1?
Answered by
Michael
I'll assume it is...
First, square both sides to get
y + 9 = 1
y = -8
Now plug that back into the original equation to see if it is extraneous. (An extraneous solution is one that does not work.)
√(-8 + 9) = 1
√(1) = 1
That is correct, so the answer is y = 1.
First, square both sides to get
y + 9 = 1
y = -8
Now plug that back into the original equation to see if it is extraneous. (An extraneous solution is one that does not work.)
√(-8 + 9) = 1
√(1) = 1
That is correct, so the answer is y = 1.