Asked by maya
the floor of a room is a rectangle. it has a perimeter of 22m and an area of 24 square meters.
what are the length and width of the room?
what are the length and width of the room?
Answers
Answered by
Reiny
length --- x
width --- y
x+y = 11 or y = 11-x
xy = 24
x(11-x) = 24
x^2 - 11x + 24 = 0
(x-3)(x-8) = 0
x = 3 or x = 8
if x=3, y = 8
if x = 8, y = 3
the room is 3 by 8
width --- y
x+y = 11 or y = 11-x
xy = 24
x(11-x) = 24
x^2 - 11x + 24 = 0
(x-3)(x-8) = 0
x = 3 or x = 8
if x=3, y = 8
if x = 8, y = 3
the room is 3 by 8
Answered by
Ms. Sue
This must be a closet.
The factors of 24:
3 * 8
4 * 6
2 * 12
Which of those dimensions would give a perimeter of 22 m?
The factors of 24:
3 * 8
4 * 6
2 * 12
Which of those dimensions would give a perimeter of 22 m?
Answered by
maya
im in grade 4 i don't know what that is
Answered by
Ms. Sue
Perimeter = 2 times length plus 2 times width
Answered by
maya
rieny that doesent make sense it cant be.
Answered by
Reiny
Maya, if you only in grade 4, then forget about my solution.
Go with what Ms Sue has shown you.
the room is 3 metres by 8 metres
check : 3+8 + 3+8 = 22
3x8 = 24
Go with what Ms Sue has shown you.
the room is 3 metres by 8 metres
check : 3+8 + 3+8 = 22
3x8 = 24
Answered by
maya
wow thanks rieny :)
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