Asked by Toni Jones
What volume of 1.30 M SrCl2 is needed to prepare 525 mL of 5.00 mM SrCl2?
Answers
Answered by
DrBob222
Sometimes mM can be confusing and one can avoid the confusion by converting to M.
5.00 mM = 0.005 M
M = moles/L
You know M and you know L, solve for moles = M x L = 0.005 x 0.525 = ??
Then moles = grams/molar mass
You know moles and molar mass, solve for grams.
5.00 mM = 0.005 M
M = moles/L
You know M and you know L, solve for moles = M x L = 0.005 x 0.525 = ??
Then moles = grams/molar mass
You know moles and molar mass, solve for grams.
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