Asked by thanksalot
each tablespoon of the liquid contains 95mg of aluminum hydroxide and 412mg of magnesium carbonate.how many moles of hydronium ion can be neutralized by one tablespoon of it?al(oh)3 =78g/mol
;mgCo3 =84.3 g/mol
;mgCo3 =84.3 g/mol
Answers
Answered by
thanksalot
why it is nesessary to cool down the sample before titration in antacid anlaysis ?
Answered by
DrBob222
If you take many more chemistry courses you will NOT be able to get away with using lower case for formulas. mgCo3 actually means milligrams carbon + o3 means nothing.
To solve the problem, first write the equations and balance them.
Al(OH)3 + 3H^+ ==> Al^+3 + 3H2O
Mg(OH)2 + 2H^+ ==> Mg^+2 + 2H2O
moles Al(OH)3 in 95 mg = grams/molar mass.
moles Mg(OH)2 in 412 mg = grams/molar mass.
Using the coefficients in the balanced equation, convert moles Al(OH)3 to moles H^+.
Do the same for Mg(OH)2.
Then add moles H^+ from the Al compound to moles H^+ from the Mg compound to arrive at the total moles H^+ neutralized by a table spoon of the stuff.
To solve the problem, first write the equations and balance them.
Al(OH)3 + 3H^+ ==> Al^+3 + 3H2O
Mg(OH)2 + 2H^+ ==> Mg^+2 + 2H2O
moles Al(OH)3 in 95 mg = grams/molar mass.
moles Mg(OH)2 in 412 mg = grams/molar mass.
Using the coefficients in the balanced equation, convert moles Al(OH)3 to moles H^+.
Do the same for Mg(OH)2.
Then add moles H^+ from the Al compound to moles H^+ from the Mg compound to arrive at the total moles H^+ neutralized by a table spoon of the stuff.
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