Asked by Beth
Evaluate the given expression.
d
dx
[2(x2 + 3|x|)]
1
d
dx
[2(x2 + 3|x|)]
1
Answers
Answered by
drwls
I am guessing you want the derivative of the piecewise-continuous function
f(x) = 2(x^2 + 3|x|) ,
but what does the "1" represent?
If you want the derivative at x=1, you can remove the | | signs
f(x) = 2(x^2 + 3|x|) ,
but what does the "1" represent?
If you want the derivative at x=1, you can remove the | | signs
Answered by
agrin04
For |x|, we have 2 situations.
|x| = x, for x >= 0
|x| = -x, for x < 0
So:
¤ for x>=0:
d/dx (2(x^2 + 3x)) = ?
¤ for x<0:
d/dx (2(x^2 - 3x)) = ?
|x| = x, for x >= 0
|x| = -x, for x < 0
So:
¤ for x>=0:
d/dx (2(x^2 + 3x)) = ?
¤ for x<0:
d/dx (2(x^2 - 3x)) = ?
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