Asked by Sierra
What is the pH of a solution that is comprised of 0.0843 M HCl and 0.0287 M HClO4?
Answers
Answered by
Dr Russ
Both acids are monoprotic acids and both are strong acids.
So 0.0843 M HCl will give 0.0843 M H+
and
0.0287 M HClO4 will give 0.0287 M H+
so the total H+ is
(0.0843+0.0287)M = 0.113 M
pH=-log([H+]/M)
so pH=-log(0.113)
So 0.0843 M HCl will give 0.0843 M H+
and
0.0287 M HClO4 will give 0.0287 M H+
so the total H+ is
(0.0843+0.0287)M = 0.113 M
pH=-log([H+]/M)
so pH=-log(0.113)
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