Whoever wrote this question does not realize that the force they are asking for is NOT a friction force. It is a lateral force on the EDGE of the blade that keeps the skater on a circular path.
You should mention this to your teacher, if you have one.
If it were a friction force, it would be opposite to the direction of motion and would result in a slowing down of the skater.
The force that are asking for is the centripetal force, M V^2/R
You can do the numbers yourself
50kg iceskater turns a bend at 7m/sec. if the radius of the curve is 5 meters, what is the centripetal force provided by the friction between the blade of the skate and the ice?
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