Asked by Jon
A capacitor network has two capacitors in series: 150nF and 120nF. The potential difference between point a on the outer side of the 150nF capacitor and point b on the outer side of the 120nF capacitor is 120nF.
a) total charge of the network= 2.4uC
b) charge on each capacitor= 2.4uC, and 2.4uC (in series)
c)total energy in the network=43.2 uJ
d) total energy in each capacitor
i set up two equations V1+V2=36
And C1V1^2/2 + C2V2^2/2 = 43.2
I tried solving but i keep getting the wrong answer
a) total charge of the network= 2.4uC
b) charge on each capacitor= 2.4uC, and 2.4uC (in series)
c)total energy in the network=43.2 uJ
d) total energy in each capacitor
i set up two equations V1+V2=36
And C1V1^2/2 + C2V2^2/2 = 43.2
I tried solving but i keep getting the wrong answer
Answers
Answered by
Jon
I know the answers are 19.2, and 24.0..
just not sure how to get there
just not sure how to get there
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