Asked by Patrice
??Jack has two spheres one has radius of 12 and the other has a diameter of 12. What is the difference between two spheres?
Answers
Answered by
Bosnian
Diameter=2*Radius
Radius=Diameter/2
Radius of first sphere R1=12
Radius of second sphere R2=D2/2=12/2=6
R1/R2=12/6=2
R1/R2=2
Area of sphere=4*pi*R^2
Area of first sphere A1=4*pi*12^2=
4*pi*(2*6)^2=4*pi*4*6^2
Area of second sphere A2=4*pi*6^2
A1/A2=(4*pi*4*6^2)/(4*pi*6^2)=4
A1/A2=4
Volume of a sphere:
V=(4/3)*pi*R^3
Volume of first sphere:
(4/3)*pi*12^3=
(4/3)*pi*(2*6)^3=(4/3)*pi*8*6^3
Volume of second sphere:
(4/3)*pi*6^3
V1/V2=[(4/3)*pi*8*6^3]/[(4/3)*pi*6^3]=8
V1/V2=8
V2/V1=8
First sphere have 2x larger Radius, 4x larger Area and 8x larger Volume
Radius=Diameter/2
Radius of first sphere R1=12
Radius of second sphere R2=D2/2=12/2=6
R1/R2=12/6=2
R1/R2=2
Area of sphere=4*pi*R^2
Area of first sphere A1=4*pi*12^2=
4*pi*(2*6)^2=4*pi*4*6^2
Area of second sphere A2=4*pi*6^2
A1/A2=(4*pi*4*6^2)/(4*pi*6^2)=4
A1/A2=4
Volume of a sphere:
V=(4/3)*pi*R^3
Volume of first sphere:
(4/3)*pi*12^3=
(4/3)*pi*(2*6)^3=(4/3)*pi*8*6^3
Volume of second sphere:
(4/3)*pi*6^3
V1/V2=[(4/3)*pi*8*6^3]/[(4/3)*pi*6^3]=8
V1/V2=8
V2/V1=8
First sphere have 2x larger Radius, 4x larger Area and 8x larger Volume
Answered by
Bosnian
V1/V2=8
Answered by
Bosnian
Delete: V2/V1=8
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