Question
16y^2 - 4y + 1 = 0
I'm trying to find the roots for the equation. What do I do next after this step:
4y (4y - 1) + 1 = 0
I'm trying to find the roots for the equation. What do I do next after this step:
4y (4y - 1) + 1 = 0
Answers
Anonymous
It's impossible to solve that equation