Asked by Anonymous
                16y^2 - 4y + 1 = 0
I'm trying to find the roots for the equation. What do I do next after this step:
4y (4y - 1) + 1 = 0
            
        I'm trying to find the roots for the equation. What do I do next after this step:
4y (4y - 1) + 1 = 0
Answers
                    Answered by
            Anonymous
            
    It's impossible to solve that equation
    
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