Asked by Elizabeth

What is the area of this triangle 22 by 16 by 28 inches
Answered by bobpursley
area= sqrt (s(s-a)(s-b)(s-c))

where s is the half perimeter (1/2 perimeter) a, b, c are the three sides.
Answered by Reiny
area = √(s(s-a)(s-b)s-c)) where a,b and c are the sides
and s = (1/2)perimiter.

s = (1/2)(22+16+28) = 33
s-a = 33-22 = 11
s-b = 33 - 16 = 17
s-c = 33 - 28 = 5

Area = √(33x11x17x5) = √30855

= 11√255
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