Question

Light enters a plate of borosilicate crown glass
at an angle of 40.2 degrees  with respect to the nor-
mal to the air-glass surface. If the index of
refraction of the glass is 1.52, find the angle
made by the refracted beam with the normal.
Answer in units of .

Answer 1

Snell's law says that

sin 40.2 = 1.52 sin(theta)

theta is the angle of refraction.

Solve for it.

sin(theta) = 0.4246

theta = 25.1 degrees