Asked by leslie
Light enters a plate of borosilicate crown glass
at an angle of 40.2 degrees with respect to the nor-
mal to the air-glass surface. If the index of
refraction of the glass is 1.52, find the angle
made by the refracted beam with the normal.
Answer in units of .
at an angle of 40.2 degrees with respect to the nor-
mal to the air-glass surface. If the index of
refraction of the glass is 1.52, find the angle
made by the refracted beam with the normal.
Answer in units of .
Answers
Answered by
drwls
Snell's law says that
sin 40.2 = 1.52 sin(theta)
theta is the angle of refraction.
Solve for it.
sin(theta) = 0.4246
theta = 25.1 degrees
sin 40.2 = 1.52 sin(theta)
theta is the angle of refraction.
Solve for it.
sin(theta) = 0.4246
theta = 25.1 degrees
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.