Asked by De Angelis

A rectangular sheet of
aluminum foil is 50 centimeters long and 20 centimeters
wide, and weighs 5.4 grams. Find the thickness
of the aluminum foil in centimeters.
Answered by eb
D = kg/V = 2700kg/m^3.

5.4*10^-3 / V = 2700,
V = 5.4*10^-3 / 2.7*10^3 = 2*10^-6.

V = 0.05 * 0.02 * T = 2*10^-6,
1*10^-3*T = 2*10^-6,
T = 2*10^-6 / 1*10^-3 = 2*10^-3m = 2mm.
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