Asked by Jack
How many different points of intersection are there for x + y = 7 and y = x squared minus 7?
Answers
Answered by
Reiny
equate
x^2 - 7 = 7-x
x^2 + x - 14 = 0
this equation has two different real roots
so there are two different points of intersection.
x^2 - 7 = 7-x
x^2 + x - 14 = 0
this equation has two different real roots
so there are two different points of intersection.
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