Asked by lee
proof that x^0 = 1
x<sup>5</sup>
------------- =
X<sup>5</sup>
x*x*x*x*x
----------- = 1 =
x*x*x*x*x
x<sup>5-5</sup> = x<sup>0</sup> = 1
x<sup>5</sup>
------------- =
X<sup>5</sup>
x*x*x*x*x
----------- = 1 =
x*x*x*x*x
x<sup>5-5</sup> = x<sup>0</sup> = 1