Question
What type(s) of intermolecular force is (are) common to each of the following. (Select all that apply.)
1) Xe and methanol (CH3OH)
a)london-dispersion forces
b)dipole-dipole
c)hydrogen bonding
i put a and b but it was wrong
2)CH3OH and acetonitrile (CH3CN)
a)london-dispersion forces
b)dipole-dipole
c)hydrogen bonding
i got a b and c but it was wrong.
please explain why the answer that is correct is correct
thanks:):)
1) Xe and methanol (CH3OH)
a)london-dispersion forces
b)dipole-dipole
c)hydrogen bonding
i put a and b but it was wrong
2)CH3OH and acetonitrile (CH3CN)
a)london-dispersion forces
b)dipole-dipole
c)hydrogen bonding
i got a b and c but it was wrong.
please explain why the answer that is correct is correct
thanks:):)
Answers
Both have London forces.
Xe can't be dipole-dipole although it can be dipole-induced dipole and your instructor might be counting that as b (but I don't think that is very probable). CH3OH has hydrogen bonds; obviously Xe has no H and it can't have hydrogen bonding. So I would go with a only.
For b.
Everything has London forces.
Both are polar (therefore dipoles) but not strong ones.
CH3OH forms hydrogen bonds with other molecules of CH3OH. I don't think CH3CN is likely to form H bonds with itself so I would go with a and b.
Xe can't be dipole-dipole although it can be dipole-induced dipole and your instructor might be counting that as b (but I don't think that is very probable). CH3OH has hydrogen bonds; obviously Xe has no H and it can't have hydrogen bonding. So I would go with a only.
For b.
Everything has London forces.
Both are polar (therefore dipoles) but not strong ones.
CH3OH forms hydrogen bonds with other molecules of CH3OH. I don't think CH3CN is likely to form H bonds with itself so I would go with a and b.
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