Asked by kassi

if 50 grams of a substance with temperature of 20 degrees C and a specific heat of 2 is mixed with 200 grams of water at 40 degrees C, what will be the equilibrium temperature of the mixture?
Answered by DrBob222
heat gained by first substance + heat lost by water = 0

[mass*specific heat x (Tfinal-Tinitial)] + [massH2O x specific heat water x (Tfinal-Tnitial)] = 0
Solve for Tfinal.
Post your work if you get stuck.
Answered by tim
123
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